Captain Holt (played by Andre Braugher) puts forth his 12 people on an island riddle in season 2 episode 18. There are two possible results. Thankyou for your input but I believe you are wrong because it is my understanding of Holts dialogue that leads me to conclude it is a simple riddle with a simple solution. Death by roo roo. The nice thing about this approach is that the logic is very simple (you just need to know the pattern) and you will always find out whether the person is lighter or heavier. 2.B.1 if left heavy Press question mark to learn the rest of the keyboard shortcuts. There are 12 men on an island. Before that I didnt really get what you were doing. Solution 2c. Can a VGA monitor be connected to parallel port? This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. seesaw: S1 S2 S3 R1 R2 R3 (balanced) Jordan's line about intimate parties in The Great Gatsby? Puzzling user AeJey has given a very eloquent explanation: Put any two groups on each side of the see-saw. You have to figure out which Islander is the heaviest using a seesaw. Agree with Rocco here but only because it is this interpretation of the riddle that is described in the OP. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. The See-Saw. There is also a see-saw on the island. At this point we just weight S4 against a If the seesaw reverses, ether 4 or 5 is the oddly weighted one. Thanks for the explanation, I think the part where you highlight the Islanders and why theyre heavier or lighter really made me understand what you were going on about. Weigh 12 against 1 to find out whether 12 is heaver or lighter. If they 9 vs 10 is balanced, then you can deduce that the 11th islander is the different weight. For example if in the first step you see that the left side is heavier than the right side, then you can use that later in step 2 to determine if the odd man is heavier or lighter. That's not true. There is also a see-saw on the island. sideline: S1 S2 S3 S4 Scenario Two, from your original 4x4 weighing: 2. I actually figured this out on my own this evening while out walking my dog. Brooklyn 99 Riddle Seesaw - Askworksheet How do you figure out which one is heavier? Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. Jordan's line about intimate parties in The Great Gatsby? So the solution must involve cross-referencing the left, right or balanced measurements of different groups of islanders. The whole lighter OR heavier is the big monkey wrench here. Proceed to solution 1a. Answer explained - step by step Number the islanders 1 to 12 First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. Put any two groups on each side of the see-saw. Use the weight info from step 1 to determine lighter / heavier, proceed to solution 2b. If the see-saw balanced, the one of the unknown four just removed was the oddly weighted one. Pardon the handwriting, its usually better. No Scenarios, No Cases, Just The Simple Answer.Instagram: https://www.instagram.com/lifeprojxFacebook: https://www.facebook.com/lifeprojx I am just looking for a little tweak to this answer. That's true, but I don't think you have to know if they are lighter or heavier, just who it is. This page contains affiliate links, which means we may earn a small amount of money if a reader clicks through and makes a purchase. Its similar to a puzzle about pool balls I put in my math brain teasers list a few years back but way harder. :p, haha yeah loved the episode! And if they are, then weigh 9, 10, 11 vs 1, 2, and 3. The island has no scales but there is a see-saw. L: sit on the left, R: sit on the right, -: dont sit on the seesaw. You cant solve this puzzle? 1 v 12). ", (Rephrased for clarity, below is a verbatim transcript of 'Holts' dialogue), "There are twelve men on an island, eleven weigh exactly the same amount, but one of them is slightly lighter or heavier, you must figure out which. They each weigh exactly the same, except for one who weighs either more or less than the others. After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). If they are equal, A4 is heavier. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (heavy) 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. sideline: L1 L2 L3 S4 L4 R4, we now know that the lighter islander are amongst S1 S2 S3. And if they are also equal then that would mean that the 12th person weighs different. Let's say 'abc' and '456'. Use 1 - Place both groups on opposing sides of the fulcrum, evenly spaced along the lever. Can someone suggest how we can modify the answer above ? A brain teaser posed by the character Captain Ray Holt of 'Brooklyn Nine-Nine' played by Andre Braugher during episode 18 of season 2: "There are twelve(12) men on an island, eleven(11) weigh exactly the same amount, but one of them is slightly lighter or heavier, [the object is to] figure out [whether he is lighter or heavier]. The riddle: There are 12 islanders on an island. Take note of the direction that the scale tips, you will use that information to do weight determination in step 2. Each step here corresponds to one weighing. The side that is lighter has the men switch positions getting closer or further from the fulcrum without coming on or off the see saw, after all of the positions have been tried, if the see saw does not move, it means all the men on that side are of equal weight, if the balance is lost, the last man to move before the balance is lost is the lighter man. You must figure out which. rev2023.3.1.43268. There is an island with 12 islanders. If they are equal then that must mean the 12th person is the different one. Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. Similar logic will help us design all further comparisons. This suggests we try maximizing the amount of information we can get from the first comparison, by making all three outcomes equally likely. are patent descriptions/images in public domain? How can you find out which islander is the one that has a different weight? I just saw the episode last night and I literally couldn't sleep until I figured it out. Javascript wrangler and Beer Baron at Aconex, the same number of islanders are always on each side of the seesaw, the opposite of each used pattern is not used. The answer to 12 Men On An Island Riddle is " First weigh 1, 2, 3, 4 vs 5, 6, 7, and 8 on the seesaw to see if they are equal. 2: Place the man from your pair who was on the lower end of the see-saw . IF the measurement is equal then the odd man is 12. Ackermann Function without Recursion or Stack. The best answers are voted up and rise to the top, Not the answer you're looking for? The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. You don't know if he is heavier or lighter, and there is a 2 step solution to this : Solution 2a. Wow how did this even get 8 upvotesmind boggling. You cannot determine lighter, heavier, proceed to solution 2c. Connect and share knowledge within a single location that is structured and easy to search. Thus in principle we can get log 2 27 bits from the three comparisons. we know it is either R1 or L1. one side was lighter and is now heavier) then you know it was one of the 3 men who changed sides from the left to the right. Logic Logic puzzles require you to think. All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. Thus we need to log224 bits of information to solve the puzzle. (Third Use), If the see saw is not balanced, remove one from each end. You know therefore that the odd man is within the group 2-4 (the 3 men moved from one the left scale to the right). Applications of super-mathematics to non-super mathematics. The riddle, as you'll recall, is this: There are twelve men on an island. Would the reflected sun's radiation melt ice in LEO? Example for condition 1: put three "unknowns" against three "knowns". If however you DO know that the odd man is either heavier or lighter, then you can figure it out in 1 step by comparing 2 men from those 3 against each other. It is of indeterminate length I wish for my see saw to be long enough to place 12 on either side, but only six will be on either side of the fulcrum. Proceed to step 2. Split the men into two(2) groups 'abcdef' and '123456'. (Second Use). Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. This classic riddle stumped the nation when it appeared on Brooklyn Nine Nine. Weapon damage assessment, or What hell have I unleashed? How do you do it? 12 Islanders Riddle Puzzle from Brooklyn 99. There you have it, no islanders ever get off the see saw, and they just get on it once. If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. In other news,did Pete Davidson tattoo a kid? @emdee - Here is the link that you posted in the question. The second measurement was unequal, but the balance of weight shifted. Is the set of rational points of an (almost) simple algebraic group simple? Before you read on, I just want to say that this problem drove me nuts. 42 votes, 14 comments. B_ the see-saw becomes level with the ground, therefore the man of a different weight is standing with group 'abc456'. If they are equal then. I like Rosa's answer squeeze until fatty confesses. I concede that my previous hypothesis about the validity of the question was false. In either scenario, the steps are basically the same. -v, 1 split the 12 islanders into three groups Have something to tell us about this article? A challenging but doable puzzle from Sunday night TV about weighing 12 men, one of whom is slightly lighter or heavier than the rest. Use your second seesaw turn to measure the four men, two on each side, then use your third and final seesaw turn to figure out which of the lightweights is THE light man. Otherwise the one who stayed is the oddly weighted one. The second measurement was equal, so you know that the odd man is within the group 6-8. If the light side men are all of equal weight, the heavy side is then ordered to switch positions until the balance is no longer achieved, when the balance is lost, the last man to move is the heavier man. Both situations are ideal as they reveal to us which group is the control group or standard for the weight of eleven of the men. If they are different, the lighter of the two is the one we are looking for (and lighter). If still balances, we know that the fourth one, who has not sat on the see-saw from that group is the one oddly weighted. Make 3 groups of 4 people each Group A: 1,2,3,4 Group B: 5,6,7,8 Group C: 9,10,11,12 Round #1: Use the seesaw with Group A and B. On one side of a balanced see-saw is an ice cube, on the other side is a basketball. If nothing happens, download Xcode and try again. now compare R2 and R3. What is the arrow notation in the start of some lines in Vim? we weigh S1 against S2. Try that and see where it takes you. Now, weigh the remaining eight men on the seesaw, four on each side. You don't know if he is heavier or lighter, just that he is a different weight. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. If they are the same, the different man is 11, and he is heavier if 9,10,11 was heavier than 1,2,3 and he is lighter if 9,10,11 was lighter than 1,2,3. Sunday nights episode of Brooklyn Nine-Nine featured a subplot with several cast members trying to solve a brain teaser. now switch R1 R2 R3 and S2 S3 S4 AND switch R1 AND L1. If A > B, then weigh A1, B1, and B2 against B3, B4, and C1. Your aim is to find out which person weighs a different amount. It is impossible to know both for sure in only three steps.). Software Engineer Author has 67 answers and 176.2K answer views 3 y Number each of the 12 people from 1 through 12. 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